2.2 Allocating output between two plants
Intuitively, if the marginal cost of production is higher in one plant than another and the firm is producing a positive output in the plant with the higher marginal cost, then the firm can reduce its cost by transferring one unit of output from the plant with the higher marginal cost to the plant with the lower marginal cost. If the marginal cost is an increasing function of output in each plant, then after the transfer of the unit of output the difference between the marginal costs will be less than it was originally. So long as the difference is positive, the firm can reduce its costs further by transferring output to the plant with the lower marginal cost. Only when the marginal costs in both plants are the same, or the output in the plant with the higher marginal cost is zero, can the firm not reduce its cost any further.
Thus at the cost-minimizing allocation of output
- either the firm produces a positive output in each plant and the marginal cost in each plant is the same
- or the firm produces all its output in one plant, and the marginal cost in this plant is no greater than the marginal cost at the output of zero in the other plant.
- Example
-
A firm owns two plants, with VC functions
VC1(y1) = 3y2How should it allocate output between the two plants if it wants to produce 80 units of output?
1
VC2(y2) = y2
2.It should choose the allocation of output that makes the marginal cost in each plant the same, if there is such an allocation. First find the marginal costs:
SMC1(y1) = 6y1Thus the firm wants to choose y1 and y2 such that y1 + y2 = 80 and
SMC2(y2) = 2y2.6y1 = 2y2,or6y1 = 2(80−y1),or8y1 = 160,ory1 = 20 and y2 = 60.
- Example
-
A firm owns two plants, with VC functions
VC1(y1) = 2y1How should it allocate output between the two plants if it wants to produce y units of output?
VC2(y2) = y2.The marginal cost functions in the two plants are
SMC1(y1) = 2Thus, no matter how the firm allocates its output, the marginal cost in the first plant is higher than the marginal cost in the second plant. Thus the cost-minimizing allocation assigns all the output to the second plant:
SMC2(y2) = 1.y*1 = 0 and y*2 = y.